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9a^2+46a+5=0
a = 9; b = 46; c = +5;
Δ = b2-4ac
Δ = 462-4·9·5
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-44}{2*9}=\frac{-90}{18} =-5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+44}{2*9}=\frac{-2}{18} =-1/9 $
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